CBSE Class 11-science Answered

Find the percentage ionization of 0.2 M acetic acid solution, whose dissociation constant is 1.8×10^(-5)

Asked by chhajednidhish60 | 03 Feb, 2018, 08:31: AM

Expert Answer

space space space space space space space space space space space space space space space space space space CH subscript 3 COOH space space space space space space leftwards harpoon over rightwards harpoon space space CH subscript 3 COO space to the power of minus space space space space plus space space space space space straight H to the power of plus Initial space conc. space space space space space space space space space space 0.2 space space space space space space space space space space space space space space space space space space space space space 0 space space space space space space space space space space space space space space space space space space 0 At space equm space space space space space space space space space space 0.2 left parenthesis 1 minus straight alpha right parenthesis space space space space space space space space space space space space 0.2 straight alpha space space space space space space space space space space space space space space 0.2 straight alpha space space space space space space space space space space space space straight K subscript straight a space space end subscript space equals space space space space fraction numerator left square bracket CH subscript 3 COO space to the power of minus space right square bracket left square bracket space straight H to the power of plus right square bracket over denominator space CH subscript 3 COOH space end fraction space space 1.8 cross times 10 to the power of 5 space space equals space space fraction numerator open parentheses 0.2 straight alpha close parentheses squared over denominator 0.2 minus 0.2 straight alpha end fraction space space space space space space space space space space space space space space straight alpha space space equals space 0.95 space cross times 10 to the power of negative 2 end exponent percent sign space Ionisation space equals space space 0.95 space cross times 10 to the power of negative 2 end exponent space cross times 100 percent sign space Ionisation equals space 9.95 percent sign

Answered by Varsha | 03 Feb, 2018, 02:52: PM

CBSE Class 11-science Answered

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