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CBSE Class 12-science Answered

Compute the gravitational force and the electric force between the electron and the proton in the hydrogen atom if they are 5.3 x 10-11 meters apart.  Then calculate the ratio of Fe to Fg.  Using the same orbital distance from above, find the orbital speed and the centripetal acceleration (in g’s) of an electron orbiting the nucleus of a hydrogen atom (assuming the orbit to be circular)
Asked by rushabhjain.avv | 09 May, 2020, 03:35: PM
answered-by-expert Expert Answer
F subscript e equals fraction numerator K q 1 q 2 over denominator r squared end fraction F subscript e equals fraction numerator 9 cross times 10 to the power of 9 cross times 1.6 cross times 10 to the power of negative 19 end exponent cross times 1.6 cross times 10 to the power of negative 19 end exponent over denominator open parentheses 5.3 cross times 10 to the power of negative 11 end exponent close parentheses squared end fraction G r a v i t a t i o n a l space f o r c e F subscript e equals fraction numerator G m subscript p m subscript e over denominator r squared end fraction F subscript G equals fraction numerator 6.7 cross times 10 to the power of negative 11 end exponent cross times 1.6 cross times 10 to the power of negative 27 end exponent cross times 9.1 cross times 10 to the power of negative 31 end exponent over denominator open parentheses 5.3 cross times 10 to the power of negative 11 end exponent close parentheses squared end fraction F subscript e over F subscript e equals fraction numerator fraction numerator 9 cross times 10 to the power of 9 cross times 1.6 cross times 10 to the power of negative 19 end exponent cross times 1.6 cross times 10 to the power of negative 19 end exponent over denominator open parentheses 5.3 cross times 10 to the power of negative 11 end exponent close parentheses squared end fraction over denominator fraction numerator 6.7 cross times 10 to the power of negative 11 end exponent cross times 1.6 cross times 10 to the power of negative 27 end exponent cross times 9.1 cross times 10 to the power of negative 31 end exponent over denominator open parentheses 5.3 cross times 10 to the power of negative 11 end exponent close parentheses squared end fraction end fraction F subscript e over F subscript e equals fraction numerator 9 cross times 10 to the power of 9 cross times 1.6 cross times 10 to the power of negative 19 end exponent cross times 1.6 cross times 10 to the power of negative 19 end exponent over denominator 6.7 cross times 10 to the power of negative 11 end exponent cross times 1.6 cross times 10 to the power of negative 27 end exponent cross times 9.1 cross times 10 to the power of negative 31 end exponent end fraction F subscript e over F subscript e equals fraction numerator 1.6 cross times 10 to the power of 40 over denominator 6.7 end fraction
F subscript e equals fraction numerator m v squared over denominator r end fraction fraction numerator K q 1 q 2 over denominator r squared end fraction equals fraction numerator m v squared over denominator r end fraction O n space s u b s t i t u t i n g space v a l u e s space w e space g e t v equals 0.69 cross times 10 to the power of 6 m divided by s a subscript c equals v squared over r a subscript c equals fraction numerator open parentheses 0.69 cross times 10 to the power of 6 close parentheses squared over denominator 5.3 cross times 10 to the power of negative 11 end exponent end fraction
 
 
Answered by Utkarsh Lokhande | 09 May, 2020, 05:26: PM

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