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CBSE Class 12-science Answered

Breakdown voltage of the capacitor are mentioned in the diagram. The breakdown voltage of the system of three capacitors will be equal to   
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Asked by prakriti12oct | 10 Aug, 2019, 01:56: AM
answered-by-expert Expert Answer
Equivalent capacitance C :-  1/C = (1/4)+(1/12)+(1/6) = (1/2)    or    C = 2 μf
 
Charge on 4μf capacitor at  breakdown voltage 10 V,  (  q1 = C1V ) ,   4×10 = 40 μC  
Charge on 12μf capacitor at  breakdown voltage 6 V,  (  q2 = C2V ) ,   12×6 = 72 μC 
Charge on 6μf capacitor at  breakdown voltage 8 V,  (  q3 = C3V ) ,   6×8 = 48 μC 
 
Since equal charge is hold by each capacitor when capacitors are connected in series, 
we can charge the given system of capacitors only 40 μC
 
For charge of 40 μC, voltage applied to the given system of capacitors,  V = q/C  =  40 μC /2 μf  = 20 V
 
Hence breakdown voltage of the given system of capacitors = 20 V
Answered by Thiyagarajan K | 10 Aug, 2019, 08:26: AM

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