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CBSE Class 12-science Answered

An oil drop of 12 excess electrons is held stationary under a constant electric field of 2.55 × 104 N/C in Millikan"s oil drop experiment. The density of the oil is 1.26 g/cm³. What do you think will be the radius of the drop? (g = 9.81 m/s² , e = 1.6 × 10-19)
Asked by Topperlearning User | 16 Apr, 2015, 10:39: AM
answered-by-expert Expert Answer

 

In Millikan"s oil drop experiment, a negatively charged oil drop is suspended in a uniform electric field such that its weight is balanced by the electric force due to the field. The net force on the charge is zero.

  Thus,          

Or,              

Since q is due to the excess electrons,

Therefore,

The density of the oil is given

Thus, the volume of the oil drop is

 

Assuming the drop to be spherical, we have

Answered by | 16 Apr, 2015, 12:39: PM

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