CBSE Class 11-science Answered
an ideal gas is enclosed in a cylinder at pressure 2 atm and temperature 300k the mean time between two successive collisions is 6×10–⁸s if the pressure is doubled and temperature is increased to 500k the mean time between two successive collisions will be close to
Asked by ifrayaseen31 | 28 Oct, 2023, 09:26: AM
Expert Answer
Initial pressure P = 2 atm ; Final pressure = 5 atm ;
Initial temperature = 300 K ; final temperature = 500 K
Mean free path λ between moleculer collisions is ,
where k is Boltzman constant , T is temperature , d is moleculer size and P is pressure .
Mean free path λ between moleculer collision is directly proportional to temperature T and
inversely proportional to pressure P
Average speed vavg of gas molecules is proportional to square root of temperature ,
Mean time τ between collision = ( mean free path ) / ( average speed )
( please note that τ in above expression is greek symbol tau not temperature )
Hence mean time between collision at 500 K and 4 atm. pressure is calculated as
Answered by Thiyagarajan K | 28 Oct, 2023, 11:24: AM
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