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CBSE Class 12-science Answered

An electron moving horizontally with a velocity of 4 x 10^4  enters a region of uniform magnetic field of 10^-5T , acting vertically downwards as shown in figure. Draw its trajectory and find out the time it takes to come out of the region of magnetic field.
Asked by sanjanaprabha9 | 18 Jul, 2020, 12:54: AM
answered-by-expert Expert Answer
A s space t h e space e l e c t r o n space i s space m o v i n g space p e r p e n d i c u l a r space t o space t h e space m a g n e t i c space f i e l d comma space t h e r e f o r e space i t space w i l l space p e r f o r m space a space c i r c u l a r space m o t i o n.
R a d i u s space i s space g i v e n space b y
r equals fraction numerator m v over denominator B q end fraction
r equals fraction numerator 9.1 cross times 10 to the power of negative 31 end exponent cross times 4 cross times 10 to the power of 4 over denominator 10 to the power of negative 5 end exponent cross times 1.6 cross times 10 to the power of negative 19 end exponent end fractionT i m e equals fraction numerator D i s tan c e space c o v e r e d space over denominator V e l o c i t y end fraction
I f space i t space c o m p l e t e s space t h e space s e m i space c i r c l e space t h e n
T equals fraction numerator pi r over denominator V end fraction
O n space s u b s t i t u t i n g space t h e space v a l u e s space w e space c a n space g e t space t h e space t i m e space t a k e n space b y space t h e space e l e c t r o n.
Answered by Utkarsh Lokhande | 18 Jul, 2020, 12:39: PM
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