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  1. ABCDis a parellelogram,o is any point on diagnol AC.prove :ar(AOB)=ar(AOD)
  2. IN quad. ,ABCD.P is amidpt. of AC prove :ar(ABCD)=ar(BCPD)
  3. IN CYCLIC QUAD. If ang.B-angD=60 deg. .prove smaller of both is also is 60 deg

Asked by aninadathoorsridharan 25th January 2016, 6:42 AM
Answered by Expert
Answer:

In space cyclic space quadrilateral space ABCD comma Given space that space angle straight B minus angle straight D space equals space 60 degree............. left parenthesis 1 right parenthesis  Also space opposite space angles space of space cyclic space quadilateral space are space supplementry. space angle straight B plus angle straight D space equals space 180 degree............. left parenthesis 2  Adding space eq left parenthesis 1 right parenthesis space and space eq left parenthesis 2 right parenthesis comma  2 angle straight B space equals 240 degree angle straight B space equals 120 degree  Substitute space value space of space space angle straight B space in space eq space left parenthesis 1 right parenthesis 120 degree minus angle straight D space equals space 60 degree  angle straight D space equals space 60 degree

Answered by Expert 25th January 2016, 6:02 PM
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