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CBSE Class 12-science Answered

a source of sound and listner are approching each other with aspeed of 40m/s . the apparent fequency of note produced by the source is 400CPS. then ,its true frequency in cps is 
Asked by Atulcaald | 31 May, 2018, 09:40: PM
answered-by-expert Expert Answer
The frequency ν observed by the observer is given by
begin mathsize 12px style nu space equals space nu subscript 0 open parentheses fraction numerator V space plus space V subscript O over denominator V plus V subscript s end fraction close parentheses space end style
where ν and ν0 are observed and true frequency respectively. V is speed of sound.
Vo and Vs are spped of observer and speed of source respectively.
 
In the given question Vo and Vs are same i.e., 40 m/s. Hence ν = ν0  . There is no frequency change
Answered by Thiyagarajan K | 08 Jun, 2018, 05:06: PM

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