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ICSE Class 9 Answered

A solid weighs 0.144 kgf in air,0.128 kgf in water and 0.136 kgf in liquid .calculate relative density of solid and liquid?  
Asked by samridhsharma512 | 26 May, 2018, 01:48: PM
answered-by-expert Expert Answer
Mass of solid in air = 0.144 kg
 
Mass of solid in water = 0.128 kg
 
loss of weight in water = 0.144 - 0.128 = 0.016 kg = 16 gm
 
loss of weight in water is due to weight of displaced water that has same volume of solid.
 
hence displaced volume of water  =  mass/density = (16×10-3) / 1000 = 16×10-6 m3
 
Volume of solid = 16×10-6 m3  ; density of solid = 0.144/(16×10-6 m3 ) = 9000 kg/m3 ;
 
loss of weight in liquid = 0.144 - 0.136 = 0.008 kg
 
displaced liquid mass = 0.008 kg ;
 
displace liquid volume is same as volume of solid = 16×10-6 m3
 
density of liquid = mass/ volume = 0.008 / (16×10-6) = 2000 kg/m3
Answered by Thiyagarajan K | 28 May, 2018, 10:48: AM

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