NEET Class neet Answered
A particle starts from the point of origin (10m 37° North of East ) and then turns 4m towards north then turns 5m 37° North of West! Where is the distance traveled and the displacement found by partical ??
Asked by surabhilakhara7299 | 24 May, 2021, 08:00: AM
Expert Answer
Graphical method.
Let us consider scale factor 1 cm = 5 m to draw the graph of displacement vectors.
We start from origin and draw vector OA of lenth 5 cm that makes angle 37o with x-axis .
Vector OA represents the displacement of 10 m in the direction 37o North of East .
Next draw a vector AB of length 2 cm starting from A in the direction of y-axis.
Vector OB represents the displacement of 4 m in North .
Next draw a vector BC of length 2.5 cm starting from B that makes angle 37o with -x axis.
Vector BC represents the displacement of 5 m in the direction 37o North of west.
Net displacement from graph = 6.8 cm that equals 13.6 m real displacement
Total distance = ( 10 + 4 + 5 ) = 19 m
-------------------------------------------------------------
Vector method by resolving components
= ( 10 cos37 
+ 10 sin37 
) m
= 4 m
= -5 cos37 + 5 sin37 
= + + = [ 5 cos37 + ( 15 sin37 + 4 ) ] m = ( 4 + 13 ) m | | = 
| = Total distance = ( 10 + 4 + 5 ) = 19 m
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