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ICSE Class 9 Answered

A  jeweller claims to make  ornaments of pure gold  of relative density  19.3 .  Customer buys from him a Bangle  of weight   25.25 gf.  The customer then weighs The Bangle  under water and find its weight  what is 23.075 g  with the help of suitable  calculation explain the whether  The Bangle  is of pure gold or not. 
Asked by rk2783740 | 31 Aug, 2018, 06:37: PM
answered-by-expert Expert Answer
loss of weight in water = 25.250 - 23.075 = 2.175gf
 
loss of weight in water = mass of displaced water = (volume of displaced water)×(density of water) = 2.175gf
 
if we consider density of water = 1 g/cc, then,  volume of displaced water = volume of bangle = 2.175 cm3 
 
mass of bangle, if it is made by pure gold of relative density 19.3 = 2.175×19.3 ≈ 42 gf
 
Conclusion :- Bangle is not made by pure gold of relative density 19.3
Answered by Thiyagarajan K | 03 Sep, 2018, 12:11: PM

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