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A cylindrical solid of area of cross-section 0.0004m2 and length 0.30 m is completely immersed in water.Calculate (i) Weight of solid in SI system (ii) Upthrust acting on solid in SI system (iii) Apparent weight of solid in (a) Water (b) Alcohol [Take g =10m/s2 ; Density of water =1000 kg/m3 ; Density of Alcohol =780 kg/m3; Density of solid = 1500 kg/m3]
Asked by akshitabiju304 | 02 Nov, 2020, 02:12: PM
answered-by-expert Expert Answer
Volume of soild = crosssection area × length = 4 × 10-4 m2 × 0.3 m = 1.2 × 10-4 m3 
 
mass of solid = volume × density = 1.2 × 10-4 × 1500 = 0.18 kg
 
(i) weight of solid = 0.18 kg × 9.8 m/s2 = 1.764 N
 
(ii) Upthrust = Volume of solid × density of liquid × acceleration due to gravity
 
Upthrust = 1.2 × 10-4 × 1000 × 9.8 = 1.176 N
 
(iii) Apparent weight in water = weight - upthrust = ( 1.764 - 1.176 ) N = 0.588 N
 
Upthrust in Alcohol = 1.2 × 10-4 × 780 × 9.8 = 0.917 N
 
Apparent weight in Alcohol  = ( 1.764 - 0.917 ) N = 0.847 N
Answered by Thiyagarajan K | 02 Nov, 2020, 02:44: PM

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