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A car loaded with sand is moving with spped v .a hole is present at bottom of car through sand is falling continuously.then after time t velocity of car is increase or decrease
Asked by ashutosharnold1998 | 31 Aug, 2019, 12:34: AM
Expert Answer
Let us assume car is moving with constant speed V and there is no external force.
(Let us assume the force generated by engine just balances the frictional force between car tyres and ground.
Hence net force acting on moving car is zero)
Let M be the mass of car and m be the mass of sand falling from car in every second.
At the time of falling , sand particles get a horizontal velocity V .
Hence if we apply momentum conservation for time instants of before sand falling and after time falling we get,
M×V = m×V + (M-m)×V1 .....................(1)
eqn.(1) is rewritten as, M×V = m×(V - V1) + M×V1 ..................(2)
Though (V - V1) is negligible, m×(V-V1) is +ve . Hence from eqn.(2), we get V1 < V
Hence the speed of car decreases
Answered by Thiyagarajan K | 31 Aug, 2019, 08:57: AM
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