CBSE Class 11-science Answered
A body moving with uniform acceleration travels a distance of 24m and 64m rurind the first two equal consecutive intervals of time each of duration 4 second.
Determine the initial velocity and acceleration of moving body.
Asked by tps.mjmdr | 06 Jul, 2018, 09:09: PM
Expert Answer
let initial velocity u m/s and acceleration a m/s2 .
let distance travelled in first 4 s interval is S1, it is given by,
from (1), we get, u+2×a = 6 .....................(2)
after 4 sec, velocity = u+a×t = u+4a
distance S2 travelled by second 4 s interval is given by
from (3), we get u +6×a = 16 .......................(4)
By solving (2) and (4), we get u = 1 m/s , a = 2.5 m/s2
Answered by Thiyagarajan K | 07 Jul, 2018, 11:18: AM
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