CBSE Class 12-science Answered
A beam of light of wavelength 400 nm is incident normally on a right angled prism as shown. It is observed that the light just grazes along the surface AC after falling on it. Given that the refractive index of the material of the prism varies with the wavelength λ as per the relation
calculate the value of b and the refractive index of the prism material for a wavelength λ = 5000 .[Given θ = sin-1(0625)]
Asked by Topperlearning User | 08 Jul, 2014, 03:02: PM
Expert Answer
Given λ = 400n = 400 x 10-9m
i1 = 0, r1 = 0
r1 + r2 = θr2 = θ r1= θ
i2 =90o
From snell's law
b =(4 x 10-7)2 x 0.4m2 = 6.4 x 10-14m2
Now putting λ = 5000 = 5 x 10-7m
μ' = 1.2 + = 1.2 + 0.256 = 1.456
Answered by | 08 Jul, 2014, 05:02: PM
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