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a,b,c are positive integers.

5a+5b+2ab=92

5b+5c+2bc=136

5c+5a+2ac=244

find 7a+8b+9c

Asked by aahnik.mohanty 2nd February 2018, 7:30 PM
Answered by Expert
Answer:
begin mathsize 16px style 5 straight a plus 5 straight b plus 2 ab equals 92 space space
5 straight b plus 5 straight c plus 2 bc equals 136 space space
5 straight c plus 5 straight a plus 2 ac equals 244

straight a plus straight b plus 2 over 5 ab equals 92 over 5.....1
straight b plus straight c plus 2 over 5 bc equals 136 over 5......2
straight c plus straight a plus 2 over 5 ac equals 244 over 5......3
multiply space 1 space by space 3......3 straight a plus 3 straight b plus 6 over 5 ab equals 276 over 5
2 space by space 5..................5 straight b plus 5 straight c plus 2 bc equals 136
3 space by space 4..................4 straight c plus 4 straight a plus 8 over 5 ac equals 1952 over 5
add space all space
7 straight a plus 8 straight b plus 9 straight c equals 276 over 5 plus 136 plus 1952 over 5 minus 6 over 5 ab minus 2 bc minus 8 over 5 ac end style
 
 
please check correctness of your question
Answered by Expert 7th February 2018, 11:29 AM
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