CBSE Class 11-science Answered
7. State the relation between maximum range and maximum height of the projectile if the angle of projection is 45 deg
Asked by roshnibudhrani88 | 23 Mar, 2024, 05:52: PM
Expert Answer
Let u be the initial projection velocity and θ is initial projection angle. Let g be the acceleration due to gravity .
Maximum height h reached by projectile =
h = [ u2 sin2θ ] / ( 2 g )
If angle of prjection θ = 45o , then maximum height H reached by projectile is
H = u2 / (4g) ............................(1)
Range r of projectile is
r = ( u2 / g ) sin2θ
Maximum range R of projectile when θ = 45o is
R = ( u2 / g ) ............................( 2 )
From (1) and (2) , we get
R = 4 H
Answered by Thiyagarajan K | 24 Mar, 2024, 07:48: AM
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