CBSE Class 11-science Answered
6th answer
Asked by lovemaan5500 | 05 May, 2018, 06:35: PM
Expert Answer
For first experiment we have l1+e = v/(4n) ...............(1)
where l1 is the length of resonating column, e is error in measurement, v is speed of sound and n is frequency of vibrartion
for second experiment we have l2+e = 3v/(4n) ...............(2)
(2)-(1) gives (l2-l1) = 2v/(4n) = v/(2n).......................(3)
hence Δ(l2-l1) / (l2-l1) = Δv/v
Δv = 2n×Δ(l2-l1) = 2×512×(0.1+0.1) = 204.8 cm/s
Answered by Thiyagarajan K | 06 May, 2018, 10:19: AM
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