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CBSE Class 12-science Answered

5th ques
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Asked by lovemaan5500 | 22 Feb, 2020, 10:16: PM
answered-by-expert Expert Answer
Radius R of circular path of charged particle is given by,
 
R = ( m v ) / ( q B )  .................(1)
 
If kinetic energy E = (1/2)mv2  , then eqn.(1) is written in terms of kinetic energy as
 
R = ( 2 E m )1/2 / ( q B ) ............(2)
 
Hence radius R begin mathsize 14px style proportional to end style ( √m / q )
 
Let us  take mass of proton as m,  charge of proton as q and radius Rp .
 
Deutron mass is 2m and charge is q , hence radius RD = √2 Rp
 
Alpha particle mass is 4m and charge is 2q , hence Radius Rα = ( 4m )1/2 /  (2q) = Rp
 
Hence , we get,  Rp : RD : Rα = 1 : √2 : 1
Answered by Thiyagarajan K | 23 Feb, 2020, 10:25: AM

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CBSE 12-science - Physics
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CBSE 12-science - Physics
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