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∆ABC is a right-angled triangle with ∠B = 90o. By Pythagoras theorem,
∆ABC is a right-angled triangle with ∠B=90o.
By Pythagoras theorem,
AC2 = BC2 + AB2
In ∆XYZ, XY2 = YZ2 + XZ2, so
In ∆XYZ, XY2 = YZ2 + XZ2, so, ∠Z = 90o
∆ABC is a right-angled triangle with AB = 5 cm, AC = 3 cm and ∠C = 90o. Find BC.
∆ABC is a right-angled triangle with ∠C = 90o.
AB2 = BC2 + AC2 25 − 9 = AC2 AC = 4 cm
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