Zeroes
Asked by abhishek11 | 30th May, 2009, 02:39: PM
Expert Answer:
The problem can be solved by using remainder theoram.
f(x)=2x³ - x² - 13x -6
Now f(3)=0
Hence x-3 is a factor.
Rewriting f(x),
2x³ - x² - 13x -6= 2x2(x-3)+5x( x-3)+2(x-3)=(2x2+5x+2)(x-3)=(2x2+x+4x2)(x-3)(2x+1)(x+2)(x+3)
Hence roots are x= -1/2 , -2 . 3
Answered by | 30th May, 2009, 07:41: PM
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