Zeroes

Asked by abhishek11 | 30th May, 2009, 02:39: PM

Expert Answer:

The problem can be solved by using remainder theoram.

f(x)=2x³ - x² - 13x -6

Now f(3)=0

Hence x-3 is a factor.

Rewriting f(x),

2x³ - x² - 13x -6= 2x2(x-3)+5x( x-3)+2(x-3)=(2x2+5x+2)(x-3)=(2x2+x+4x2)(x-3)(2x+1)(x+2)(x+3)

Hence roots are x= -1/2 , -2 . 3

 

Answered by  | 30th May, 2009, 07:41: PM

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