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x+√y=7 and √x+y=11 find the value of x and y
Asked by Mukeshthakur1403 | 08 Jul, 2019, 11:24: PM Expert Answer
x + √y = 7 and √x + y = 11
Consider
√x + y = 11
√x  = 11 - y
Squaring on both sides
x = 121 - 22y + y2
Put x = 121 - 22y + y2 in the equation x + √y = 7
Let √y = z
we get 121 + z4 - 22z2 + z = 7
We get factors z = ± 1, ± 2, ± 3, ± 6, ± 19, ± 57, ± 114
z = 3 satisfies the equation.
Now find the value of x and y we get x = 4 and y = 9
Answered by Renu Varma | 09 Jul, 2019, 09:58: AM
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