x+√y=7 and √x+y=11 find the value of x and y

Asked by Mukeshthakur1403 | 8th Jul, 2019, 11:24: PM

Expert Answer:

x + √y = 7 and √x + y = 11
Consider
√x + y = 11
√x  = 11 - y 
Squaring on both sides
x = 121 - 22y + y2 
Put x = 121 - 22y + y2 in the equation x + √y = 7
Let √y = z
we get 121 + z4 - 22z2 + z = 7
We get factors z = ± 1, ± 2, ± 3, ± 6, ± 19, ± 57, ± 114
z = 3 satisfies the equation.
Now find the value of x and y we get x = 9 and y = 4

Answered by Sneha shidid | 9th Jul, 2019, 09:58: AM