ICSE Class 10 Answered
x+1/x-1=3x-7/2x-5
Asked by pruthaveshmenesj01052 | 06 Jun, 2021, 21:42: PM
![begin mathsize 14px style fraction numerator x plus 1 over denominator x minus 1 end fraction space equals space fraction numerator 3 x minus 7 over denominator 2 x minus 5 end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/ec9636d5f26b01d9108655f8fad1ee54.png)
After cross multiplying , we get
( x + 1 ) ( 2x - 5 ) = ( 3x -7 ) ( x - 1 )
2x2 -3x -5 = 3x2 - 10x + 7
X2 - 7x + 12 = 0
(x-4) ( x-3 ) = 0
x = 4 or x = 3
-------------------------------------------------
Alternate method by ratio and proportion
![begin mathsize 14px style fraction numerator x plus 1 over denominator x minus 1 end fraction space equals space fraction numerator 3 x minus 7 over denominator 2 x minus 5 end fraction end style](https://images.topperlearning.com/topper/tinymce/cache/ec9636d5f26b01d9108655f8fad1ee54.png)
If (a/b) = (c/d ) , then we have ( a + b ) / (a - b ) = ( c + d ) / ( c - d ) .........................(2)
Using above property of ratio and proportion, given eqn.(1) is written as
( x / 1 ) = [ ( 3x - 7 ) + ( 2x - 5 ) ] / [ (3x-7 ) - (2x -5 ) ]
x = ( 5x - 12 ) / ( x -2 )
x2 - 2x = 5x - 12
x2 - 7x +12 = 0 or ( x-4) ( x- 3 ) = 0
Hence , we get , x = 3 or x = 4
Answered by Thiyagarajan K | 20 Sep, 2021, 12:34: PM
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