CBSE Class 12-science Answered
Why is the electric field in a capacitor after introduction of dielectric= (sigma -sigma p)/ epsilon .
Where sigma is surface charge density and sigma p is surface charge density of the polarised dielectric.
![question image](https://images.topperlearning.com/topper/new-ate/topr_400230482377339278IMG20190704213041.jpeg)
Asked by prakriti12oct | 04 Jul, 2019, 21:31: PM
Because the electric field
polarizes the dielectric as a result charges are induced on the surface of the dielectric which induces electric field
. But the induced electric field
is in opposite direction to the original electric field E. Therefore the net electric field is given by
![E equals sigma over epsilon subscript 0](https://images.topperlearning.com/topper/tinymce/cache/dedf39b33dc32e6d38280e5bbed815ce.png)
![E subscript P equals sigma subscript P over epsilon subscript 0](https://images.topperlearning.com/topper/tinymce/cache/b25c461c68af3561e848cd5e1f0c36a4.png)
![E subscript P equals sigma subscript P over epsilon subscript 0](https://images.topperlearning.com/topper/tinymce/cache/b25c461c68af3561e848cd5e1f0c36a4.png)
![E equals fraction numerator sigma minus sigma subscript P over denominator epsilon subscript 0 end fraction](https://images.topperlearning.com/topper/tinymce/cache/4871dda86aaa10157faf86f2ad49c68b.png)
Answered by Utkarsh Lokhande | 05 Jul, 2019, 09:16: AM
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