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CBSE Class 11-science Answered

what volume of 5M Na2so4 must be added to 25ml of 1M Bacl2 solution to produce 10g Baso4

Asked by ashutosharnold1998 | 18 May, 2020, 12:25: PM
Expert Answer
N a subscript 2 S O subscript 4 space plus space B a C l subscript 2 rightwards arrow 2 N a C l space plus space B a S O subscript 4
M o l a r space m a s s space o f space N a subscript 2 S O subscript 4 equals 142 space g divided by m o l
M o l a r space m a s space o f space B a S O subscript 4 equals 233.3 space g divided by m o l
M o l a r space m a s s space o f space B a C l subscript 2 equals 208.3 space g divided by m o l

N u m b e r space o f space m o l e s space o f space t h e space s u l f a t e space i o n equals space N u m b e r space o f space m o l e s space o f space B a r i u m space i o n space i n space B a S O subscript 4
N u m b e r space o f space m o l e s space o f space b a r i u m space i o n space i n space 10 space g space b a r i u m space s u p h a t e equals space N u m b e r space o f space m o l e s space o f space B a S O subscript 4 equals fraction numerator 10 over denominator 233.4 end fraction equals 0.0428 space moles
Number space of space moles space of space sulphate space ions equals 0.0428 space moles
Number space of space moles space of space Na subscript 2 SO subscript 4 equals straight M cross times straight V equals 5 cross times straight V equals 0.0428
space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space straight V equals 8.57 cross times 10 to the power of negative 3 end exponent space straight L space equals 8.57 space mL
space space
Answered by Ravi | 19 May, 2020, 07:50: PM
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