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ICSE Class 10 Answered

what is the resistance offered to the nut
Asked by suneelmsc | 14 Jul, 2020, 11:13: PM
Expert Answer
E = 0.5 N 
Effort arm = distance between the fulcrum and the effort = 2+ 18 = 20 cm 
Load = Resistance offered by the nut =? 
Load arm = 2 cm 
 
We know, the principle of lever, 
Effort x Effort arm = Load x load arm 
Thus, 
0.5 N x 20 cm = L x 2 
Thus, 
L thin space equals space fraction numerator 0.5 cross times 20 over denominator 2 space end fraction space equals space 5 space N space 
Thus, the resistance offered by the nut will be 5 N 
Answered by Shiwani Sawant | 15 Jul, 2020, 07:46: PM

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