what is the range of root (xsquare-4)?can you show the process?

Asked by pulakananda | 15th Feb, 2012, 12:54: PM

Expert Answer:

In the given equation Since x2 - 4 is in root ,
So x2 - 4 >= 0 , (x-2)(x+2) >= 0 , x = (-inf,-2] U (2,inf)
For x = 2,-2 , Value of the function is 0 and for x = inf,-inf , Value of the function is inf
Range is [0,inf)

Answered by  | 15th Feb, 2012, 07:16: PM

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