find relation between x,y and z x² + 4y² + 9z² - 2xy - 3xz - 6yz = 0
Asked by sundramsingh1707
| 11th Jun, 2022,
05:20: PM
Expert Answer:
x3 + (2y)3 + (3z)3 - x (2y) (3z) = ( x+ 2y + 3z) ( x2 + 4y2 + 9z2 - 2xy - 6yz -3xz )
since ( x2 + 4y2 + 9z2 - 2xy - 6yz -3xz ) = 0 , LHS of above expression is zero
Hence we get , x3 + (2y)3 + (3z)3 = x (2y) (3z) = 6xyz
Answered by Thiyagarajan K
| 12th Jun, 2022,
11:11: AM
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