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what is the answer of this question
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Asked by jeelsojitra26 | 18 Jul, 2022, 06:33: PM
answered-by-expert Expert Answer
stack l i m with x rightwards arrow 0 to the power of plus below open parentheses fraction numerator 3 space ln squared x space plus space 5 space ln space x space plus space 6 over denominator 1 space plus space ln squared x end fraction close parentheses
equals stack l i m with x rightwards arrow 0 to the power of plus below open parentheses fraction numerator 3 space plus space begin display style fraction numerator 5 over denominator ln space x end fraction end style space plus space begin display style fraction numerator 6 over denominator ln squared x end fraction end style over denominator begin display style fraction numerator 1 over denominator ln squared x end fraction end style space plus space 1 end fraction close parentheses
equals stack l i m with x rightwards arrow 0 below open parentheses fraction numerator 3 space plus space begin display style fraction numerator 5 over denominator ln space x end fraction end style space plus space begin display style fraction numerator 6 over denominator ln squared x end fraction end style over denominator begin display style fraction numerator 1 over denominator ln squared x end fraction space plus space 1 end style end fraction close parentheses
equals fraction numerator 3 plus 0 plus 0 over denominator 0 plus 1 end fraction
equals 3
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