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lim 1/ √3n^2+1
n to infinity?
![question image](https://images.topperlearning.com/topper/new-ate/topr_4081727331322956IMG20200913WA0003.jpeg)
Asked by srav03031985 | 13 Sep, 2020, 11:40: AM
To find lim n to infinity 1/sqrt{3n2 + 1}
![limit as straight n rightwards arrow infinity of fraction numerator 1 over denominator square root of 3 straight n squared plus 1 end root end fraction equals fraction numerator 1 over denominator square root of 3 cross times infinity plus 1 end root end fraction equals 1 over infinity equals 0](https://images.topperlearning.com/topper/tinymce/cache/9e6dfc4bb712e747b104160cdc07c23a.png)
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