what is mot and vbt
Asked by danishkhatik | 17th Feb, 2018, 09:49: AM
Molecular orbital theory
- Molecular orbital theory asserts that atomic orbitals no longer hold significant meaning after atoms form molecules. Molecular orbital theory holds electrons reside in molecular orbitals that are distributed over the entire molecule.
- Atomic orbitals of comparable energy and proper symmetry combine together to form molecular orbitals. The total number of orbitals is conserved; the number of molecular orbitals equals the number of original atomic orbitals.
- When atomic orbitals interact, if added them it results in a bonding orbital and if subtracted then an antibonding orbital is obtained. Antibonding orbitals are denoted with an asterisk (*).
- The movement of electrons in a molecular orbital is influenced by all the nuclei of combining atoms.
Valence bond theory:
- It does not give quantitative interpretation of magnetic data.
- It does not explain the colour exhibited by coordination compounds.
- It does not give a quantitative interpretation of the thermodynamic or kinetic stabilities of coordination compounds.
- It does not make exact predictions regarding the tetrahedral and square planar structures of 4-coordinate complexes.
- It does not distinguish between weak and strong ligands.
According to this theory, the metal atom or ion under the influence of
ligands can use its (n − 1)d, ns, np or ns, np or nd orbitals for hybridisation
to yield a set of equivalent orbitals of definite geometry such as octahedral, tetrahedral and square planar.
These hybridised orbitals are allowed to overlap with ligand orbitals which can donate electron pairs for bonding.
Answered by Varsha | 17th Feb, 2018, 12:15: PM
- What is the oxidation number of Ni in Ni(CO)4 ?
- What is synergic effect
- Explain structure of ferrocyanide ion? Explain the coordinating bonding between Fe and cyanide ion? How many cyanide ion form covalent and coordinate bond? Explain full structure with detail
- The magnetic moment for two complexes of empirical formula Ni(NH3)4 (NO3)2.2H2O is zero and 2.84 BM repectively. The second complex is not a neutral complex. The correct formula and geometry of the first complex is : (1) [Ni(H2O)2(NO3)2].4NO3 = Tetrahedral (2) [Ni(NH3)4] (NO3)2.2H2O = Tetrahedral (3) [Ni(NH3)4](NO3)2.2H2O = Square planar (4) [Ni(NH3)4(H2O)2](NO3)2 = Octahedral
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