Explain structure of ferrocyanide ion? Explain the coordinating bonding between Fe and cyanide ion? How many cyanide ion form covalent and coordinate bond? Explain full structure with detail
Asked by govtsecschoolnayaganv051
| 30th Jul, 2018,
05:33: PM
Expert Answer:
The structure of ferrocyanide ion is
Structure of ferrocyanide ion:
Fe (II) attached with six cyanide ions gives octahedral geometry.
Formation of Ferrocyanide ion. [Fe(CN)6]4-
Here Fe has +2 oxidation state, hence
The resulting complex ion is octahedral and diamagnetic as it does not contain any unpaired electron.
In the cyanide ion, the carbon is bonded with nitrogen by the triple covalent bond.
And six cyanide ions are coordinately bonded with Fe (II) ion to give the complex ion [Fe(CN)6]4-
Answered by Ramandeep
| 30th Jul, 2018,
07:56: PM
- Among Fe++ and Co+++, which metal cation is more paramagnetic and why?
- 𝕍𝔹𝕋 𝕠𝕗 [ℂ𝕠(ℂ2𝕆4)3]^-3
- Coordination compounds predict the hybridisation and geometry of [Mn F6]3- on the basis of valence bond theory with diagram showing electron filling.
- Pl answer
- Pl answer
- the primary and secondary valencies of the central metal ion in the [Co(NH3)Cl3
- What is the oxidation number of Ni in Ni(CO)4 ?
- What is synergic effect
- The magnetic moment for two complexes of empirical formula Ni(NH3)4 (NO3)2.2H2O is zero and 2.84 BM repectively. The second complex is not a neutral complex. The correct formula and geometry of the first complex is : (1) [Ni(H2O)2(NO3)2].4NO3 = Tetrahedral (2) [Ni(NH3)4] (NO3)2.2H2O = Tetrahedral (3) [Ni(NH3)4](NO3)2.2H2O = Square planar (4) [Ni(NH3)4(H2O)2](NO3)2 = Octahedral
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change