Wedge problem II.

Asked by  | 9th Apr, 2009, 10:26: PM

Expert Answer:

Note the forces on the body of mass m

i) mass of body mg acts downwards.

ii) mg is resolved into components along and perpendicular to the plane.

iii) pseudo force F equal and opposite to ma where a is the acceleration of the block. This can also be resolved in to components parallel and perpendicular to the plane.

iv) N is the normal force.

Since the block does not slip on the wedge, the forces along the wedge are in equilibrium. Equating these forces the correct option is d)

Answered by  | 2nd May, 2009, 02:05: PM

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