Wedge problem II.
Asked by | 9th Apr, 2009, 10:26: PM
Note the forces on the body of mass m
i) mass of body mg acts downwards.
ii) mg is resolved into components along and perpendicular to the plane.
iii) pseudo force F equal and opposite to ma where a is the acceleration of the block. This can also be resolved in to components parallel and perpendicular to the plane.
iv) N is the normal force.
Since the block does not slip on the wedge, the forces along the wedge are in equilibrium. Equating these forces the correct option is d)
Answered by | 2nd May, 2009, 02:05: PM
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