Use the mirror equation to deduce that
The virtual image produced by a convex mirror is always diminished in size.
Asked by prakriti12oct | 27th Jun, 2019, 02:20: AM
mirror equation :- ................................(1)
where v is distance from pole of mirror to image, u is distance from pole of mirror to object and f is focal length.
sign convention :- v is positive because image always formed right side behind the mirror.
u is -ve because object is at left side in front of mirror
f is +ve for convex mirror
After applying sign convention , we get ................................(2)
when object is at infinity, (1/u) → 0 , hence v = f ( highly diminished image formed at focal point)
when object moves from infinity to pole , (1/u) > 0 and keep on increasing, hence v will keep on decrease.
Hence v which is the distance between pole and image is constrained between focal point and pole.
Hence v is always less than u. Hence magnification , m = - v/u is always <1 or virtual image size is always diminished
Answered by Thiyagarajan K | 27th Jun, 2019, 10:12: AM
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