CBSE Class 10 Answered
urgent
Asked by 2806rahul | 16 May, 2010, 08:50: PM
Expert Answer
cot θ - cot3θ = 1/tan θ - 1/tan3θ = (tan3θ - tanθ)/tanθ tan3θ .......(1)
Now,
[cot θ/(cot θ - cot3θ)] + [tan θ/(tan θ - tan3θ)] =
Using (1) to replace the denominator in first term,
[tanθ tan3θcot θ/((tan3θ - tanθ)] + [tan θ/(tan θ - tan3θ)] =
[tan3θ/((tan3θ - tanθ)] + [tan θ/(tan θ - tan3θ)] = ... tanθ cotθ = 1
[- tan3θ/((tanθ - tan3θ)] + [tan θ/(tan θ - tan3θ)] =
(tan θ - tan3θ)/(tan θ - tan3θ) = 1
Regards,
Team,
TopperLearning.
Answered by | 17 May, 2010, 07:11: AM
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