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CBSE Class 9 Answered

Two years ago a father was five times as old as his son two years later his age will  be 8 years more than 3 times the age of the son find their present age
Asked by Ankujsingla | 25 Sep, 2018, 09:47: PM
answered-by-expert Expert Answer
 
Let the present age father = x years and
son's present age = y years 
According to the first condition,
(x - 2) = 5(y -2)
x - 5y = -8   ...........(i)
According to the second condition,
(x + 2) = 3(y + 2)+ 8
x - 3y = 12  ........(ii)
 
Solving(i) and (ii) simultaneously, we get
 
y = 10 and x = 42
Therefore the present age of father is 42 years and present age of son is 10 years.

Answered by Yasmeen Khan | 26 Sep, 2018, 10:51: AM

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