Two equal charges are placed at a separation  of 1.0 m. what should be the magnitude of the charges so that the force between them euals weight of a 50 kg person?

Asked by haroonrashidgkp | 19th Apr, 2018, 08:47: PM

Expert Answer:

Force F = (q2) / [ (4πε0) r2 ]; q = 1 C , F = 50×9.8 N , ε0 = 8.85 × 10-12 F/m
 
Separation distance r = [ 1012 / (4π×8.85×50×9.8) ]1/2 = 4283 m

Answered by Thiyagarajan K | 19th Apr, 2018, 10:55: PM

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