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Two charge of 1 coulomb each are placed at a distance 9*10^-9m. Electric force between them will be
Asked by bhuvanshetty1340 | 19 Apr, 2020, 19:42: PM
answered-by-expert Expert Answer
By Coulomb's law,
 
Fc =( k q1 q2 )/ r2 
k ≈ 9×109 Nm2 /C2 
 
Fc = ( 9×109 × 1 × 1) / ( 9 ×10-9 )2 
 
Thus, electric force between the two charges is,
Fc = 0.11 × 109 N 
Answered by Shiwani Sawant | 19 Apr, 2020, 20:47: PM
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