trigonometry
Asked by suchet_r | 5th Dec, 2009, 10:18: PM
Expert Answer:
(sinA - 2sin3 A)/(2cos3 A - cosA) =
sinA(1-2sin2A)/[cosA(2cos2A -1)] =
sinA(sin2A + cos2A - 2sin2A)/[cosA(2cos2A -(sin2A + cos2A))] =
sinA(cos2A - sin2A)/[cosA(cos2A -sin2A)] =
tanA
Regards,
Team,
TopperLearning.
Answered by | 6th Dec, 2009, 08:55: PM
Related Videos
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change