trigonometry

Asked by suchet_r | 5th Dec, 2009, 10:18: PM

Expert Answer:

(sinA - 2sin3 A)/(2cos3 A - cosA) =

sinA(1-2sin2A)/[cosA(2cos2A -1)] =

sinA(sin2A + cos2A  - 2sin2A)/[cosA(2cos2A -(sin2A + cos2A))] =

sinA(cos2A  - sin2A)/[cosA(cos2A -sin2A)] =

tanA

Regards,

Team,

TopperLearning.

Answered by  | 6th Dec, 2009, 08:55: PM

Pre Board Assessment
Ask Doubt

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.