CBSE Class 11-science Answered
This question is spinning my head.. Please help..
![begin mathsize 16px style According space to space the space given space condition space given space sequence space is space in space straight A. straight P.
fraction numerator straight a subscript 1 plus straight a subscript 3 over denominator 2 end fraction equals straight a subscript 2...... left parenthesis straight i right parenthesis
2 straight a subscript 2 plus 2 straight a subscript 4 plus 2 straight a subscript 6 plus..... plus 2 straight a subscript 2012 equals 2 cross times 3018
2 straight a subscript 2 plus 2 straight a subscript 4 plus 2 straight a subscript 6 plus..... plus 2 straight a subscript 2012 equals 6036
From space left parenthesis straight i right parenthesis
open parentheses straight a subscript 1 plus straight a subscript 3 close parentheses plus open parentheses straight a subscript 3 plus straight a subscript 5 close parentheses plus.... plus open parentheses straight a subscript 2011 plus straight a subscript 1 close parentheses equals 6036
2 straight a subscript 1 plus 2 straight a subscript 3 plus 2 straight a subscript 5 plus...... plus 2 straight a subscript 2011 equals 6036
2 open parentheses straight a subscript 1 plus straight a subscript 3 plus straight a subscript 5 plus...... plus straight a subscript 2011 close parentheses equals 6036
straight a subscript 1 plus straight a subscript 3 plus straight a subscript 5 plus...... plus straight a subscript 2011 equals 3018....... left parenthesis ii right parenthesis
Adding space left parenthesis straight i right parenthesis space and space left parenthesis ii right parenthesis
Sum space of space all space the space numbers space equals space 3018 plus 3018 equals 6036
end style](https://images.topperlearning.com/topper/tinymce/cache/de127e40dbf366afbb6ff807c88d613e.png)
Answered by Sneha shidid | 29 Nov, 2017, 11:06: AM
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