CBSE Class 11-science Answered
<div>This is the second time I am asking the same question. This is irritating and all, but you explained the whole blabber which I already knew in my previous question without 'actually' solving the equation. Could you kindly, this time, "PLEASE" solve the question 'explicitly' so that I may actually feel thankful?</div>
<div>The question, again, is :</div>
<div>Prove that (2<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=18d0e52c351a213b87661c3117a37b6e.png" alt="square root of 3" align="middle" />+3)sin<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=31c361c3cc58cdb507dd0c1c79aeb1ac.png" alt="theta" align="middle" />+2<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=18d0e52c351a213b87661c3117a37b6e.png" alt="square root of 3" align="middle" />cos<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=31c361c3cc58cdb507dd0c1c79aeb1ac.png" alt="theta" align="middle" /> lies between -(2<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=18d0e52c351a213b87661c3117a37b6e.png" alt="square root of 3" align="middle" />+<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=ac4e047dae78ab6f3155f0fab77153f2.png" alt="square root of 15" align="middle" />) and (2<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=18d0e52c351a213b87661c3117a37b6e.png" alt="square root of 3" align="middle" />+<img class="Wirisformula" src="https://images.topperlearning.com/topper/tinymce/integration/showimage.php?formula=ac4e047dae78ab6f3155f0fab77153f2.png" alt="square root of 15" align="middle" />).</div>
<div> </div>
<div>THIS TIME, PLEASE, GIVE THE SOLUTION, EXPLANATION, AND THE COMPLETE SUBSTITUTION OF VALUES AT WHICH POINT YOU LEFT IN THE PREVIOUS SOLUTION!</div>
Asked by Akshat Bharadwaj | 04 Jun, 2014, 05:44: PM
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