CBSE Class 10 Answered
The near point of a person is at 40 cm from the eye.Find the power of the lens he should ....
Asked by | 22 Jul, 2008, 03:24: PM
Expert Answer
Using the equation :
(1/v)-(1/u)=1/f
we have:
(100/25)-(100/40)=1/f
So power=1/f= 1.5 D
Answered by | 22 Jul, 2008, 09:31: PM
Application Videos
Concept Videos
CBSE 10 - Physics
Asked by agankitgupta938 | 18 Apr, 2024, 04:29: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by infinityupgraded | 13 Apr, 2024, 08:17: AM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by suryamr2019 | 08 Mar, 2024, 04:32: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by saurabhjd527 | 30 Jan, 2024, 07:55: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by subrasixty | 13 Jan, 2024, 05:05: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by nandanagnair | 17 Dec, 2023, 03:44: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by namish1088 | 16 Nov, 2023, 08:09: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by 0 0 | 19 Oct, 2023, 03:51: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by bubbynaik77 | 29 Sep, 2023, 09:34: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by gurcharansingh37306 | 10 Sep, 2023, 12:53: PM
ANSWERED BY EXPERT