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ICSE Class 10 Answered

The bob of a simple pendulum is released from rest from one extreme end of a vertical height of 2cm above its mean position.Assuming 60% loss in energy, find the velocity of the bob at its mean position.
Asked by cbiswajit | 20 Sep, 2019, 11:03: PM
Expert Answer
When the bob of a simple pendulum is at extreme the total energy possessed by it is in the form of potential energy
PE=mgh
P E equals m g 0.02
When the bob is released there is loss of 60% energy so remaining enrgy when it reaches mean position would be
E n e r g y equals 40 over 100 cross times m g 0.02
when the bob is at the mean position the enrgy possessed by the bob is kinetic energy
40 over 100 cross times m cross times 10 cross times 0.02 equals 1 half m v squared V squared equals 0.16 v equals 0.4 m divided by s v equals 40 c m divided by s
Answered by Utkarsh Lokhande | 21 Sep, 2019, 08:40: AM

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