The atomic weight of two elements A and B are 20u and 40u respectively.If x g of A contains y atoms, how many atoms are present in 2x g of B?
Asked by Prince Sonu | 18th Apr, 2013, 09:35: PM
We are given that the atomic masses of the two elements A and B are 20 and 40 respectively. Also, we are given that the number of atoms in amount x g of element A is y. Therefore
number of moles of A in x g of A = mass / molar mass = (x / 20)
number of atoms in x grams of A = number of moles X Avogadro's number
= (x / 20) X 6.023 X 1023 = y (1)
mass of element B = 2x
number of moles of B in 2x g of B = mass / molar mass = (2x / 40)
number of atoms in 2x grams of B = number of moles X Avogadro's number
= (2x / 40) X 6.023 X 1023
= (x / 20) X 6.023 X 1023
But this is equal to y [from (1)]
Therefore the number of atoms in 2x grams of B is the same as x grams of A that is y.
We are given that the atomic masses of the two elements A and B are 20 and 40 respectively. Also, we are given that the number of atoms in amount x g of element A is y. Therefore
number of moles of A in x g of A = mass / molar mass = (x / 20)
number of atoms in x grams of A = number of moles X Avogadro's number
= (x / 20) X 6.023 X 1023 = y (1)
mass of element B = 2x
number of moles of B in 2x g of B = mass / molar mass = (2x / 40)
number of atoms in 2x grams of B = number of moles X Avogadro's number
= (2x / 40) X 6.023 X 1023
= (x / 20) X 6.023 X 1023
But this is equal to y [from (1)]
Therefore the number of atoms in 2x grams of B is the same as x grams of A that is y.
Answered by | 19th Apr, 2013, 09:24: PM
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