CBSE Class 10 Answered
The angle elevation of the top Q of a vertical tower PQ from a point Xon the ground is 60 degree . at a point Y, 40 m verticaaly above X, the angle of elevation is 45 degree . find the height of the tower PQ and the distance XY.
Asked by Deepshikha deepak | 26 Dec, 2013, 08:48: PM
Expert Answer
In triangle YRQ,
tan 45 = QR/ YR
This gives YR = x
or XP = x [ As YR = XP ] ...... (1)
Now, in triangle XPQ,
tan 60 = PQ / PX
V3 = x+40/x [Using(1)]
This gives:
x = 40 / V3 - 1
x = 20 (V3 + 1) = 54.64 m
(By rationalisation)
So, height of the tower, PQ = x + 40 = 54.64 + 40 = 94.64 m
In triangle XPQ,
sin 60 = PQ / XQ
V3/2 = 94.64/ XQ
This gives XQ = 109.3 m
Answered by | 26 Dec, 2013, 11:24: PM
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