CBSE Class 10 Answered
The accleration of a particle moving in a straight line varies with displacement as a =2s, velocity of a particle is zero at zero displacement. Find corresponding velocity-displacement equation.
Asked by acv27joy | 19 May, 2018, 07:06: PM
Expert Answer
acceleration dv/dt = 2×s , where s is displacement and v is speed at time t;
Let us assume time dependent functional form of displacement s is of the following form
s = ekt ................................(1)
ds/dt = k×ekt = k×s ........................(2)
d2s/dt2 = k2×ekt = k2×s.....................(3)
but given equation is d2s/dt2 = 2×s .....................(4)
from eqn.(3) and eqn.(4), we can write k = √2 ...........(5)
velocity-displacement relation from eqn.(2) is given by
v = √2×s .....................(6)
eqn.(6) satisfies the given condition v= 0 when s = 0
Answered by Thiyagarajan K | 20 May, 2018, 11:07: AM
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