CBSE Class 9 Answered
solve x^2+2x+5
Asked by | 15 Sep, 2008, 12:53: PM
Expert Answer
we know that ax2+bx+c = 0 has its roots equal to
x = ( -b ± (b2-4ac) ) /2a
here a=1 , b=2, c=5
putting the values of a,b,c
x = ( -2 ±(22-4*5) ) /2 = ( -2 ±-16 ) /2 = -1 2i where i=-1
so the values of x are imaginary.
it can also be seen from the fact that (b2-4ac) = -16 <0 which means roots of this equation are not real.
Answered by | 15 Sep, 2008, 06:15: PM
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