CBSE Class 8 Answered
Solve using laws of exponent a-3×b-7/a2×b-3
Asked by garmaan204 | 03 Jun, 2020, 07:52: AM
![begin mathsize 16px style fraction numerator straight a to the power of negative 3 end exponent cross times straight b to the power of negative 7 end exponent over denominator straight a squared cross times straight b to the power of negative 3 end exponent end fraction
equals straight a to the power of negative 3 end exponent over straight a squared cross times straight b to the power of negative 7 end exponent over straight b to the power of negative 3 end exponent
equals straight a to the power of negative 3 minus 2 end exponent cross times straight b to the power of negative 7 plus 3 end exponent
equals straight a to the power of negative 5 end exponent cross times straight b to the power of negative 4 end exponent
equals 1 over straight a to the power of 5 cross times 1 over straight b to the power of 4 end style](https://images.topperlearning.com/topper/tinymce/cache/7da2056058f5fdf5f7356825260f84f6.png)
Answered by Yasmeen Khan | 03 Jun, 2020, 09:12: AM
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