Solve using laws of exponent a-3×b-7/a2×b-3

 

 

Asked by garmaan204 | 3rd Jun, 2020, 07:52: AM

Expert Answer:

begin mathsize 16px style fraction numerator straight a to the power of negative 3 end exponent cross times straight b to the power of negative 7 end exponent over denominator straight a squared cross times straight b to the power of negative 3 end exponent end fraction
equals straight a to the power of negative 3 end exponent over straight a squared cross times straight b to the power of negative 7 end exponent over straight b to the power of negative 3 end exponent
equals straight a to the power of negative 3 minus 2 end exponent cross times straight b to the power of negative 7 plus 3 end exponent
equals straight a to the power of negative 5 end exponent cross times straight b to the power of negative 4 end exponent
equals 1 over straight a to the power of 5 cross times 1 over straight b to the power of 4 end style

Answered by Yasmeen Khan | 3rd Jun, 2020, 09:12: AM