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Solve Q97 in the photo
Asked by Vidushi412 | 04 Mar, 2019, 02:32: AM
Expert Answer
The reaction takes place as:
Cyclohexene + H2 → Cyclohexane
Given:
ΔH = -119 kJ
Enthalpy of formation of cyclohexane = - 156 kJ/mol
So, the enthalpy of formation of cyclohexane = -156-(-119) kJ = -37 kJ/mol
Cyclohexene has one double bond and benzene have three double bonds,
As ΔH cyclohexene = -156 kJ/mol, for each double bond the energy decreases by an amount of +119 kJ/mol and therefore the introduction of three double bonds (to form benzene) energy required = 3 × 119 kJ/mol = 357 kJ/mol
So, theoretical ΔHf = (357-156) kJ/mol = 201 kJ/mol
Resonance energy = theoretical ΔHf - Observed ΔHf
= (201-49) kJ/mol
= +152 kJ/mol
Hence option b is the correct answer.
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